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Transform Your Projects with Stunning Strawberry Clipart – Click to Download Now! - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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& -2 & 1 \\
\end{vmatrix} = \mathbf{i}(2 \cdot 1 - 3 \cdot (-2)) - \mathbf{j}(1 \c...
= \mathbf{i}(2 + 6) - \mathbf{j}(1 - 3) + \mathbf{k}(-2 - 2) = \langle...
14\mathbf{v} = \langle 8, 2, -4 \rangle \quad \Rightarrow \quad \mathb...
Thus, the vector is $ \boxed{\left\langle \dfrac{4}{7}, \dfrac{1}{7},...
Question: Among all roots of the polynomial $ z^6 - z^4 + z^2 - 1 = 0...
Solution: Consider the polynomial:
z^6 - z^4 + z^2 - 1 = 0
So the roots satisfy either $ z^2 - 1 = 0 $ or $ z^4 + 1 = 0 $.
Roots from $ z^2 - 1 = 0 $:

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