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Home » Transform Your Learning Today: Discover the Essential Unit on Geometry and Shape Shifts! - AMAZONAWS

Transform Your Learning Today: Discover the Essential Unit on Geometry and Shape Shifts! - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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📌 \]Question: Find the vertex of the parabola modeling the growth rate of a climate-dependent species, given by $ y = -2x^2 + 8x - 5 $.

📌 Solution: The vertex form of a parabola $ y = ax^2 + bx + c $ has its vertex at $ x = -\frac{b}{2a} $. Here, $ a = -2 $, $ b = 8 $, so $ x = -\frac{8}{2(-2)} = 2 $. Substituting $ x = 2 $ into the equation: $ y = -2(2)^2 + 8(2) - 5 = -8 + 16 - 5 = 3 $. Thus, the vertex is at $ (2, 3) $. \boxed{(2, 3)}

📌 Question: Solve for $ v $ in the equation $ \frac{1}{2}mv^2 = \frac{3}{4}kT $, where $ m $ is mass, $ k $ is Boltzmann’s constant, and $ T $ is temperature, to express $ v $ in terms of $ k $, $ T $, and $ m $.

📌 Solution: Multiply both sides by 2: $ mv^2 = \frac{3}{2}kT $. Divide by $ m $: $ v^2 = \frac{3kT}{2m} $. Take the square root: $ v = \sqrt{\frac{3kT}{2m}} $. \boxed{v = \sqrt{\dfrac{3kT}{2m}}}

📌 Question: An ornithologist tracks a bird’s migration path, which follows the quadratic equation $ y = -x^2 + 6x - 8 $. Determine the maximum height $ y $ reached during the flight.

📌 Solution: The maximum height occurs at the vertex. For $ y = -x^2 + 6x - 8 $, $ a = -1 $, $ b = 6 $, so $ x = -\frac{6}{2(-1)} = 3 $. Substitute $ x = 3 $: $ y = -(3)^2 + 6(3) - 8 = -9 + 18 - 8 = 1 $. The maximum height is $ 1 $ unit. \boxed{1}

📌 Question: Given $ f(2x + 1) = 4x^2 + 12x + 9 $, find $ f(x^2 - 3) $.

📌 Solution: Let $ u = 2x + 1 $, so $ x = \frac{u - 1}{2} $. Substitute into $ f(u) $: $ f(u) = 4\left(\frac{u - 1}{2}\right)^2 + 12\left(\frac{u - 1}{2}\right) + 9 = (u - 1)^2 + 6(u - 1) + 9 = u^2 - 2u + 1 + 6u - 6 + 9 = u^2 + 4u + 4 $. Thus, $ f(x^2 - 3) = (x^2 - 3)^2 + 4(x^2 - 3) + 4 = x^4 - 6x^2 + 9 + 4x^2 - 12 + 4 = x^4 - 2x^2 + 1 $. \boxed{x^4 - 2x^2 + 1}

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