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Home » Then \( v = \sqrt4900 = 70 \) m/s. - AMAZONAWS

Then \( v = \sqrt4900 = <>70 \) m/s. - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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📌 Solution: First, determine how many years between 1800 and 1900 inclusive are divisible by 4.

📌 The smallest is 1800 (divisible by 4), the largest is 1900.

📌 The sequence of years divisible by 4 is:

📌 1800, 1804, 1808, ..., 1900

📌 This is an arithmetic sequence with first term 1800, last term 1900, and common difference 4.

📌 Number of terms:

📌 \frac{1900 - 1800}{4} + 1 = \frac{100}{4} + 1 = 25 + 1 = 26

📌 There are 101 total years (from 1800 to 1900 inclusive).

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