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Home » From Announcement to Launch: The Mega Secrets Behind the PS3 Release Date! - AMAZONAWS

From Announcement to Launch: The Mega Secrets Behind the PS3 Release Date! - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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📌 u = rac{3 \pm \sqrt{9 - 4}}{2} = rac{3 \pm \sqrt{5}}{2}.

📌 So \( u = rac{3 + \sqrt{5}}{2} \) or \( u = rac{3 - \sqrt{5}}{2} \).

📌 Now recall \( u = rac{x+y}{x-y} \). Let \( r = rac{x}{y} \), assuming \(y

📌 e 0\). Then:

📌 rac{x+y}{x-y} = rac{r+1}{r-1}.

📌 Set this equal to each value of \(u\):

📌 Case 1:** \( rac{r+1}{r-1} = rac{3 + \sqrt{5}}{2} \)

📌 2(r+1) = (3 + \sqrt{5})(r - 1)

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A. $ \vec{v}(t) = \langle 2t, \cos(t), e^t \rangle $
B. $ \vec{v}(t) = \langle 2t, -\cos(t), e^t \rangle $
C. $ \vec{v}(t) = \langle t, \cos(t), e^t \rangle $
D. $ \vec{v}(t) = \langle 2t, \cos(t), 0 \rangle $
Correct: A $ \vec{v}(t) = \langle 2t, \cos(t), e^t \rangle $
Question: Let $ f(x, y) = x^2 + xy + y^3 $. What is the partial deriva...
A. $ x + 3y^2 $
B. $ 2x + x + 3y^2 $
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D. $ x + y + 3y^2 $

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