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Home » a_n = \sum_k=1^n L\left(\frackn\right) - AMAZONAWS

a_n = \sum_k=1^n L\left(\frackn\right) - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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0.3t > \ln(20) \approx 2.9957
t > \frac{2.9957}{0.3} \approx 9.9857
The smallest integer greater than 9.9857 is \(t = 10\).
\[ P(9) = 2e^{2.7} \approx 2 \times 14.88 = 29.76 < 40 \]
\[ P(10) = 2e^{3} \approx 2 \times 20.0855 = 40.171 > 40 \]
So, the population first exceeds 40 after \(\boxed{10}\) full days.
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Überprüfe geringfügige Anpassungen, um die Kosten zu überprüfen.
Antwort:
#### 430
Ein Student der Maschinenbauwissenschaften analysiert die Leistung ein...
Gegeben \( T = 150 \) ft·lb/s, \( \omega = 3600 \) U/min.
Einsatz in die Leistungsgleichung: \( P = \frac{150 \times 3600}{9.548...
Berechnung: \( P = \frac{540000}{9.548} \approx 56460.3 \) ft·lb/(s·s)...
Umrechnung in PS: \( 1 \text{ HP} = \frac{550 \text{ ft·lb/s}}{1} \).
Also \( P \approx \frac{56460.3}{550} \approx 102.69 \text{ HP} \).
#### 102.69

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