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📅 March 6, 2026 👤 scraface

Mar 06, 2026

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To solve this, we use the **binomial probability formula**, since each...
Numbers greater than 7 on a 10-sided die: 8, 9, 10 → 3 outcomes
Probability of success (rolling >7): $ p = \frac{3}{10} = 0.3 $
Probability of failure (rolling ≤7): $ 1 - p = 0.7 $
Number of trials $ n = 4 $
Number of successes desired $ k = 2 $
P(k) = \binom{n}{k} p^k (1 - p)^{n - k}
Substitute the values:
P(2) = \binom{4}{2} (0.3)^2 (0.7)^2 = 6 \cdot (0.09) \cdot (0.49) = 6...
Thus, the probability that exactly two of the four rolls result in a n...

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